100-105 Exam
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Q51. - (Topic 3)
Refer to the exhibit.
If the resume command is entered after the sequence that is shown in the exhibit, which router prompt will be displayed?
A. Router1>
B. Router1#
C. Router2>
D. Router2#
Answer: C
Explanation:
After resuming the telnet session by using the Enter key after it has been suspended, it will resume back to the telnet session so it will be back to the router2> prompt.
Q52. - (Topic 2)
What does a host on an Ethernet network do when it is creating a frame and it does not have the destination address?
A. Drops the frame
B. Sends out a Layer 3 broadcast message
C. Sends a message to the router requesting the address
D. Sends out an ARP request with the destination IP address
Answer: D
Explanation:
In this case, it will send out an ARP request for MAC address of the destination IP (assuming it doesn't already have it in its table) and then address it to the destination's MAC address.
Q53. CORRECT TEXT - (Topic 6)
Answer: Router>enable
Router#config terminal Router(config)#hostname Apopka 2) Enable-secret password (cisco10): Apopka(config)#enable secret cisco10 3) Set the console password to RouterPass: Apopka(config)#line console 0 Apopka(config-line)#password RouterPass Apopka(config-line)#login Apopka(config-line)#exit 4) Set the Telnet password to scan90: Apopka(config)#line vty 0 4 Apopka(config-line)#password scan90 Apopka(config-line)#login Apopka(config-line)#exit 5) Configure Ethernet interface (on the right) of router Apopka: The subnet mask of the Ethernet network 209.165.201.0 is 27. From this subnet mask, we can find out the increment by converting it into binary form, that is /27 = 1111 1111.1111 1111.1111 1111.1110 0000. Pay more attention to the last bit 1 because it tells us the increment, using the formula: Increment = 2place of the last bit 1 (starts counting from 0,from right to left), in this case increment = 25 = 32. Therefore: Increment: 32 Network address: 209.165.201.0 Broadcast address: 209.165.201.31 (because 209.165.201.32 is the second subnetwork, so the previous IP - 209.165.201.31 - is the broadcast address of the first subnet). -> The second assignable host address of this subnetwork is 209.165.201.2/27 Assign the second assignable host address to Fa0/0 interface of Apopka router: Apopka(config)#interface Fa0/0 Apopka(config-if)#ip address 209.165.201.2 255.255.255.224 Apopka(config-if)#no shutdown Apopka(config-if)#exit 6) Configure Serial interface (on the left) of router Apopka: Using the same method to find out the increment of the Serial network: Serial network 192.0.2.128/28: Increment: 16 (/28 = 1111 1111.1111 1111.1111 1111.1111 0000) Network address: 192.0.2.128 (because 8 * 16 = 128 so 192.0.2.128 is also the network address of this subnet) Broadcast address: 192.0.2.143 -> The last assignable host address in this subnet is 192.0.2.142/28. Assign the last assignable host address to S0/0/0 interface of Apopka router: Apopka(config)#interface S0/0/0 (or use interface S0/0 if not successful) Apopka(config-if)#ip address 192.0.2.142 255.255.255.240 Apopka(config-if)#no shutdown Apopka(config-if)#exit 7) Configure RIP v2 routing protocol: Apopka(config)#router rip Apopka(config-router)#version 2 Apopka(config-router)#network 209.165.201.0 Apopka(config-router)#network 192.0.2.128 Apopka(config-router)#end Save the configuration: Apopka#copy running-config startup-config Finally, you should use the ping command to verify all are working properly!
Topic 7, Mix Questions
Q54. - (Topic 3)
What OSPF command, when configured, will include all interfaces into area 0?
A. network 0.0.0.0 255.255.255.255 area 0
B. network 0.0.0.0 0.0.0.0 area 0
C. network 255.255.255.255 0.0.0.0 area 0
D. network all-interfaces area 0
Answer: A
Explanation:
Example 3-1 displays OSPF with a process ID of 1 and places all interfaces configured with an IP address in area 0. The network command.network 0.0.0.0 255.255.255.255 area 0.dictates that you do not care (255.255.255.255) what the IP address is, but if an IP address is enabled on any interface, place it in area 0.
Example 3-1.Configuring OSPF in a Single Area
router ospf 1 network 0.0.0.0 255.255.255.255 area 0
Reference: http://www.ciscopress.com/articles/article.asp?p=26919&seqNum=3
Q55. - (Topic 5)
Refer to the exhibit.
Host A can communicate with Host B but not with Hosts C or D. How can the network administrator solve this problem?
A. Configure Hosts C and D with IP addresses in the 192.168.2.0 network.
B. Install a router and configure a route to route between VLANs 2 and 3.
C. Install a second switch and put Hosts C and D on that switch while Hosts A and B remain on the original switch.
D. Enable the VLAN trunking protocol on the switch.
Answer: B
Explanation:
Two VLANs require a router in between otherwise they cannot communicate. Different VLANs and different IP subnets need a router to route between them.
Q56. - (Topic 5)
Refer to the exhibit.
An administrator cannot connect from R1 to R2. To troubleshoot this problem, the administrator has entered the command shown in the exhibit. Based on the output shown, what could be the problem?
A. The serial interface is configured for half duplex.
B. The serial interface does not have a cable attached.
C. The serial interface has the wrong type of cable attached.
D. The serial interface is configured for the wrong frame size.
E. The serial interface has a full buffer.
Answer: C
Explanation:
http://www.thebryantadvantage.com/CCNACertificationExamTutorialDirectlyConnectedSeri
alInterfaces.htm
Since the output is not forthcoming it shows that the type of cable attached is wrong,
though the cable is connected since it shows the cable type.
According to the figure DTE cable should connect to R1 on interface but while examining
using show controllers serial 0/0 command it showing that a DCE is connected so the
wrong type of cable is being used.
Q57. - (Topic 3)
Refer to the exhibit.
The internetwork is using subnets of the address 192.168.1.0 with a subnet mask of
255.255.255.224. The routing protocol in use is RIP version 1. Which address could be assigned to the FastEthernet interface on RouterA?
A. 192.168.1.31
B. 192.168.1.64
C. 192.168.1.127
D. 192.168.1.190
E. 192.168.1.192
Answer: D
Explanation:
Subnet mask 255.255.255.224 with CIDR of /27 which results in 32 hosts per.
192.168.1.31 is the broadcast address for sunbet '0'
192.168.1.64 is the network address for subnet '2'
192.168.1.127 is the broadcast address for subnet '3'
192.168.1.192 is the network address for subnet '6'
Q58. - (Topic 3)
Which two of these statements are true of IPv6 address representation? (Choose two.)
A. There are four types of IPv6 addresses: unicast, multicast, anycast, and broadcast.
B. A single interface may be assigned multiple IPv6 addresses of any type.
C. Every IPv6 interface contains at least one loopback address.
D. The first 64 bits represent the dynamically created interface ID.
E. Leading zeros in an IPv6 16 bit hexadecimal field are mandatory.
Answer: B,C
Explanation:
A single interface may be assigned multiple addresses of any type (unicast, anycast,
multicast).
Every IPv6-enabled interface must contain at least one loopback and one link-local
address.
Optionally, every interface can have multiple unique local and global addresses.
IPv6 host addresses can be assigned in multiple ways:
Static configuration
Stateless autoconfiguration
DHCPv6
When IPv6 is used over Ethernet networks, the Ethernet MAC address can be used to
generate the 64-bit interface ID for the host. This is called the EUI-64 address.
Since MAC addresses use 48 bits, additional bits must be inserted to fill the 64 bits
required.
Reference:
http://www.cisco.com/en/US/technologies/tk648/tk872/technologies_white_paper0900aecd
8026003d.pdf
Q59. - (Topic 3)
Which two commands will display the current IP address and basic Layer 1 and 2 status of an interface? (Choose two.)
A. router#show version
B. router#show ip interface
C. router#show protocols
D. router#show controllers
E. router#show running-config
Answer: B,C
Explanation:
The outputs of “show protocols” and “show ip interface” are shown below:
Global values:Internet Protocol routing is enabledSerial0/0 is up, line protocol is downInternet address is 10.1.1.1/30Serial0/1 is up, line protocol is downInternet address is 209.65.200.225/30Serial0/2 is up, line protocol is downSerial0/3 is up, line protocol is downNVI0 is up, line protocol is upInterface is unnumbered. Using address of NVI0 (0.0.0.0)Loopback0 is up, line protocol is upInternet address is 10.1.10.1/32Loopback1 is up, line protocol is upInternet address is 10.1.2.1/27Loopback6 is up, line protocol is up
Serial0/0 is up, line protocol is downInternet address is 10.1.1.1/30Broadcast address is 255.255.255.255Address determined by non-volatile memoryMTU is 1500 bytesHelper address is not setDirected broadcast forwarding is disabledMulticast reserved groups joined: 224.0.0.5Outgoing access list is not setInbound access list is not setProxy ARP is enabledLocal Proxy ARP is disabledSecurity level is defaultSplit horizon is disabledICMP redirects are always sentICMP unreachables are always sentICMP mask replies are never sentIP fast switching is enabledIP fast switching on the same interface is enabledIP Flow switching is disabledIP CEF switching is disabledIP Feature Fast switching turbo vectorIP multicast fast switching is enabledIP multicast distributed fast switching is disabledIP route-cache flags are FastRouter Discovery is disabledIP output packet accounting is disabledIP access violation accounting is disabledTCP/IP header compression is disabledRTP/IP header compression is disabledPolicy routing is disabledNetwork address translation is enabled, interface in domain insideBGP Policy Mapping is disabledWCCP Redirect outbound is disabledWCCP Redirect inbound is disabledWCCP Redirect exclude is disabled
Q60. - (Topic 7)
Which statement about native VLAN traffic is true?
A. Cisco Discovery Protocol traffic travels on the native VLAN by default
B. Traffic on the native VLAN is tagged with 1 by default
C. Control plane traffic is blocked on the native VLAN.
D. The native VLAN is typically disabled for security reasons
Answer: B