100-105 Exam
Surprising cisco 100 105
Exambible offers free demo for 100 105 icnd1 exam. "Cisco Interconnecting Cisco Networking Devices Part 1 (ICND1 v3.0)", also known as icnd 100 105 exam, is a Cisco Certification. This set of posts, Passing the Cisco ccna 100 105 pdf exam, will help you answer those questions. The ccna 100 105 pdf Questions & Answers covers all the knowledge points of the real exam. 100% real Cisco icnd1 100 105 pdf exams and revised by experts!
Q131. - (Topic 1)
Refer to the exhibit.
The host in Kiev sends a request for an HTML document to the server in Minsk. What will be the source IP address of the packet as it leaves the Kiev router?
A. 10.1.0.1
B. 10.1.0.5
C. 10.1.0.6
D. 10.1.0.14
E. 10.1.1.16
F. 10.1.2.8
Answer: E
Explanation:
Although the source and destination MAC address will change as a packet traverses a network, the source and destination IP address will not unless network address translation (NAT) is being done, which is not the case here.
Q132. - (Topic 1)
Which two characteristics apply to Layer 2 switches? (Choose two.)
A. Increases the number of collision domains
B. Decreases the number of collision domains
C. Implements VLAN
D. Decreases the number of broadcast domains
E. Uses the IP address to make decisions for forwarding data packets
Answer: A,C
Explanation:
Layer 2 switches offer a number of benefits to hubs, such as the use of VLANs and each switch port is in its own separate collision domain, thus eliminating collisions on the segment.
Q133. - (Topic 3)
Which statement is true?
A. An IPv6 address is 64 bits long and is represented as hexadecimal characters.
B. An IPv6 address is 32 bits long and is represented as decimal digits.
C. An IPv6 address is 128 bits long and is represented as decimal digits.
D. An IPv6 address is 128 bits long and is represented as hexadecimal characters.
Answer: D
Explanation:
http://www.cisco.com/en/US/technologies/tk648/tk872/technologies_white_paper0900aecd 8026003d.pdf
One of the key advantages IPv6 brings is the exponentially larger address space. The following will outline the basic address architecture of IPv6. 128-bit-long addresses Represented in hexadecimal format: Uses CIDR principles: prefix/prefix length x:x:x:x:x:x:x:x, where x is a 16-bit hex field The last 64 bits are used for the interface ID
Q134. - (Topic 3)
Which one of the following IP addresses is the last valid host in the subnet using mask 255.255.255.224?
A. 192.168.2.63
B. 192.168.2.62
C. 192.168.2.61
D. 192.168.2.60
E. 192.168.2.32
Answer: B
Explanation:
With the 224 there are 8 networks with increments of 32 One of these is 32 33 62 63 where 63 is broadcast so 62 is last valid host out of given choices.
Q135. - (Topic 2)
Refer to the exhibit.
The MAC address table is shown in its entirety. The Ethernet frame that is shown arrives at
the switch.
What two operations will the switch perform when it receives this frame? (Choose two.)
A. The switch will not forward a frame with this destination MAC address.
B. The MAC address of 0000.00aa.aaaa will be added to the MAC Address Table.
C. The MAC address of ffff.ffff.ffff will be added to the MAC address table.
D. The frame will be forwarded out of all the active switch ports except for port fa0/0.
E. The frame will be forwarded out of fa0/0 and fa0/1 only.
F. The frame will be forwarded out of all the ports on the switch.
Answer: B,D
Explanation:
If the switch already has the MAC address in its table for the destination, it will forward the frame directly to the destination port. If it was not already in its MAC table, then they frame would have been flooded out all ports except for the port that it came from.
Q136. - (Topic 3)
Refer to the graphic.
R1 is unable to establish an OSPF neighbor relationship with R3. What are possible reasons for this problem? (Choose two.)
A. All of the routers need to be configured for backbone Area 1.
B. R1 and R2 are the DR and BDR, so OSPF will not establish neighbor adjacency with R3.
C. A static route has been configured from R1 to R3 and prevents the neighbor adjacency from being established.
D. The hello and dead interval timers are not set to the same values on R1 and R3.
E. EIGRP is also configured on these routers with a lower administrative distance.
F. R1 and R3 are configured in different areas.
Answer: D,F
Explanation:
This question is to examine the conditions for OSPF to create neighborhood.
So as to make the two routers become neighbors, each router must be matched with the
following items:
1.
The area ID and its types;
2.
Hello and failure time interval timer;
3.
OSPF Password (Optional);
Q137. - (Topic 1)
Which two statements describe the operation of the CSMA/CD access method? (Choose two.)
A. In a CSMA/CD collision domain, multiple stations can successfully transmit data simultaneously.
B. In a CSMA/CD collision domain, stations must wait until the media is not in use before transmitting.
C. The use of hubs to enlarge the size of collision domains is one way to improve the operation of the CSMA/CD access method.
D. After a collision, the station that detected the collision has first priority to resend the lost data.
E. After a collision, all stations run a random backoff algorithm. When the backoff delay period has expired, all stations have equal priority to transmit data.
F. After a collision, all stations involved run an identical backoff algorithm and then synchronize with each other prior to transmitting data.
Answer: B,E
Explanation:
Ethernet networking uses Carrier Sense Multiple Access with Collision Detect (CSMA/CD), a protocol that helps devices share the bandwidth evenly without having two devices transmit at the same time on the network medium. CSMA/CD was created to overcome the problem of those collisions that occur when packets are transmitted simultaneously from different nodes. And trust me, good collision management is crucial, because when a node transmits in a CSMA/CD network, all the other nodes on the network receive and examine that transmission. Only bridges and routers can effectively prevent a transmission from propagating throughout the entire network! So, how does the CSMA/CD protocol work? Like this: when a host wants to transmit over the network, it first checks for the presence of a digital signal on the wire. If all is clear (no other host is transmitting), the host will then proceed with its transmission. But it doesn’t stop there. The transmitting host constantly monitors the wire to make sure no other hosts begin transmitting. If the host detects another signal on the wire, it sends out an extended jam signal that causes all nodes on the segment to stop sending data (think, busy signal). The nodes respond to that jam signal by waiting a while before attempting to transmit again. Backoff algorithms determine when the colliding stations can retransmit. If collisions keep occurring after 15 tries, the nodes attempting to transmit will then time out.
Q138. - (Topic 7)
Which destination IP address can a host use to send one message to multiple devices across different subnets?
A. 172.20.1.0
B. 127.0.0.1
C. 192.168.0.119
D. 239.255.0.1
Answer: D
Explanation: Multicast is a networking protocol where one host can send a message to a special multicast IP address and one or more network devices can listen for and receive
those messages. Multicast works by taking advantage of the existing IPv4 networking infrastructure, and it does so in something of a weird fashion. As you read, keep in mind that things are a little confusing because multicast was "shoe-horned" in to an existing technology. For the rest of this article, let's use the multicast IP address of 239.255.0.1. We'll not worry about port numbers yet, but make a mental note that they are used in multicast. We'll discuss that later.
Q139. - (Topic 2)
Refer to the exhibit.
What two things can the technician determine by successfully pinging from this computer to the IP address 172.16.236.1? (Choose two)
A. The network card on the computer is functioning correctly.
B. The default static route on the gateway router is correctly configured.
C. The correct default gateway IP address is configured on the computer.
D. The device with the IP address 172.16.236.1 is reachable over the network.
E. The default gateway at 172.16.236.1 is able to forward packets to the internet.
Answer: A,D
Explanation:
The source and destination addresses are on the same network therefore, a default gateway is not necessary for communication between these two addresses.
Q140. - (Topic 3)
The internetwork infrastructure of company XYZ consists of a single OSPF area as shown in the graphic. There is concern that a lack of router resources is impeding internetwork performance. As part of examining the router resources, the OSPF DRs need to be known. All the router OSPF priorities are at the default and the router IDs are shown with each router.
Which routers are likely to have been elected as DR? (Choose two.)
A. Corp-1
B. Corp-2
C. Corp-3
D. Corp-4
E. Branch-1
F. Branch-2
Answer: D,F
Explanation:
There are 2 segments on the topology above which are separated by Corp-3 router. Each
segment will have a DR so we have 2 DRs.
To select which router will become DR they will compare their router-IDs. The router with
highest (best) router-ID will become DR. The router-ID is chosen in the order below:
+
The highest IP address assigned to a loopback (logical) interface.
+
If a loopback interface is not defined, the highest IP address of all active router’s physical interfaces will be chosen.
In this question, the IP addresses of loopback interfaces are not mentioned so we will consider IP addresses of all active router’s physical interfaces. Router Corp-4 (10.1.40.40)
& Branch-2 (10.2.20.20) have highest “active” IP addresses so they will become DRs.