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How to pass ccna routing and switching icnd2 200 105 official cert guide in Apr 2021




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Q1. - (Topic 1) 

Refer to the exhibit. 

Given the output shown from this Cisco Catalyst 2950, what is the reason that interface FastEthernet 0/10 is not the root port for VLAN 2? 

A. This switch has more than one interface connected to the root network segment in VLAN 2. 

B. This switch is running RSTP while the elected designated switch is running 802.1d Spanning Tree. 

C. This switch interface has a higher path cost to the root bridge than another in the topology. 

D. This switch has a lower bridge ID for VLAN 2 than the elected designated switch. 

Answer:

Explanation: These four parameters are examined in order to make root bridge , root port , designated port. Other switch has lowest Sending Bridge ID or Sending Port ID so vlan 2 is not the root port. 

1. A lower Root Bridge ID2. A lower path cost to the Root3. A lower Sending Bridge ID4. A lower Sending Port ID 


Q2. - (Topic 3) 

What occurs on a Frame Relay network when the CIR is exceeded? 

A. All TCP traffic is marked discard eligible. 

B. All UDP traffic is marked discard eligible and a BECN is sent. 

C. All TCP traffic is marked discard eligible and a BECN is sent. 

D. All traffic exceeding the CIR is marked discard eligible. 

Answer:

Explanation: 

Committed information rate (CIR): The minimum guaranteed data transfer rate agreed to by the Frame Relay switch. Frames that are sent in excess of the CIR are marked as discard eligible (DE) which means they can be dropped if the congestion occurs within the Frame Relay network. Note: In the Frame Relay frame format, there is a bit called Discard eligible (DE) bit that is used to identify frames that are first to be dropped when the CIR is exceeded. 


Q3. - (Topic 1) 

Refer to the exhibit. 

The output that is shown is generated at a switch. Which three statements are true? (Choose three.) 

A. All ports will be in a state of discarding, learning, or forwarding. 

B. Thirty VLANs have been configured on this switch. 

C. The bridge priority is lower than the default value for spanning tree. 

D. All interfaces that are shown are on shared media. 

E. All designated ports are in a forwarding state. 

F. This switch must be the root bridge for all VLANs on this switch. 

Answer: A,C,E 

Explanation: 

From the output, we see that all ports are in Designated role (forwarding state) -> A and E 

are correct. 

The command “show spanning-tree vlan 30 only shows us information about VLAN 30. We 

don’t know how many VLAN exists in this switch -> B is not correct. 

The bridge priority of this switch is 24606 which is lower than the default value bridge 

priority 32768 -> C is correct. 

All three interfaces on this switch have the connection type “p2p”, which means Point-to-point environment – not a shared media -> D is not correct. 

The only thing we can specify is this switch is the root bridge for VLAN 3o but we can not 

guarantee it is also the root bridge for other VLANs -> F is not correct. 


Q4. - (Topic 3) 

Which two options are valid WAN connectivity methods? (Choose two.) 

A. PPP 

B. WAP 

C. DSL 

D. L2TPv3 

E. Ethernet 

Answer: A,C 

Explanation: 

On each WAN connection, data is encapsulated into frames before itcrosses the WAN link. The following are typical WAN protocols:1. High-level Data Link Control (HDLC): The Cisco default encapsulation type onpoint-to-point connections, dedicated links, and circuit-switches connections.2. PPP: Provides router-to-router and host-to-network connections over synchronous andasynchronous circuits. PPP was designed to work with several network layer protocols,including IP.3. Frame-relay: A successor to X.25. This protocol is an industry-standard, switchesdata-link layer protocol that handles multiple virtual circuits 

http://en.wikipedia.org/wiki/Wide_area_network 


Q5. - (Topic 2) 

What does a router do if it has no EIGRP feasible successor route to a destination network and the successor route to that destination network is in active status? 

A. It routes all traffic that is addressed to the destination network to the interface indicated in the routing table. 

B. It sends a copy of its neighbor table to all adjacent routers. 

C. It sends a multicast query packet to all adjacent neighbors requesting available routing paths to the destination network. 

D. It broadcasts Hello packets to all routers in the network to re-establish neighbor adjacencies. 

Answer:

Explanation: 

Introduction to EIGRP Reference: 

http://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a0080093f07.shtml 

Feasible Successors 

A destination entry is moved from the topology table to the routing table when there is a feasible successor. All minimum cost paths to the destination form a set. From this set, the neighbors that have an advertised metric less than the current routing table metric are considered feasible successors. 

Feasible successors are viewed by a router as neighbors that are downstream with respect to the destination. 

These neighbors and the associated metrics are placed in the forwarding table. 

When a neighbor changes the metric it has been advertising or a topology change occurs in the network, the set of feasible successors may have to be re-evaluated. However, this is not categorized as a route recomputation. 

Route States 

A topology table entry for a destination can have one of two states. A route is considered in the Passive state when a router is not performing a route recomputation. The route is in Active state when a router is undergoing a route recomputation. If there are always feasible successors, a route never has to go into Active state and avoids a route recomputation. 

When there are no feasible successors, a route goes into Active state and a route recomputation occurs. A route recomputation commences with a router sending a query packet to all neighbors. Neighboring routers can either reply if they have feasible successors for the destination or optionally return a query indicating that they are performing a route recomputation. While in Active state, a router cannot change the next-hop neighbor it is using to forward packets. Once all replies are received for a given query, the destination can transition to Passive state and a new successor can be selected. 

When a link to a neighbor that is the only feasible successor goes down, all routes through that neighbor commence a route recomputation and enter the Active state. 


Q6. - (Topic 2) 

Refer to the exhibit. 

The network is converged. After link-state advertisements are received from Router_A, what information will Router_E contain in its routing table for the subnets 208.149.23.64 and 208.149.23.96? 

A. O 208.149.23.64 [110/13] via 190.173.23.10, 00:00:07, FastEthernet 0/0 O 208.149.23.96 [110/13] via 190.173.23.10, 00:00:16, FastEthernet 0/0 

B. O 208.149.23.64 [110/1] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/3] via 190.173.23.10, 00:00:16, FastEthernet 0/0 

C. O 208.149.23.64 [110/13] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/13] via 190.172.23.10, 00:00:16, Serial 1/0 O 208.149.23.96 [110/13] via 190.173.23.10, 00:00:16, FastEthernet 0/0 

D. O 208.149.23.64 [110/3] via 190.172.23.10, 00:00:07, Serial 1/0 O 208.149.23.96 [110/3] via 190.172.23.10, 00:00:16, Serial 1/0 

Answer:

Explanation: 

Router_E learns two subnets subnets 208.149.23.64 and 208.149.23.96 via Router_A through FastEthernet interface. The interface cost is calculated with the formula 108 / 

Bandwidth. For FastEthernet it is 108 / 100 Mbps = 108 / 100,000,000 = 1. Therefore the cost is 12 (learned from Router_A) + 1 = 13 for both subnets - B is not correct. 

The cost through T1 link is much higher than through T3 link (T1 cost = 108 / 1.544 Mbps = 

64; T3 cost = 108 / 45 Mbps = 2) so surely OSPF will choose the path through T3 link -> 

Router_E will choose the path from Router_A through FastEthernet0/0, not Serial1/0 - C & 

D are not correct. 

In fact, we can quickly eliminate answers B, C and D because they contain at least one subnet learned from Serial1/0 - they are surely incorrect. 


Q7. - (Topic 3) 

What is the purpose of Inverse ARP? 

A. to map a known IP address to a MAC address 

B. to map a known DLCI to a MAC address 

C. to map a known MAC address to an IP address 

D. to map a known DLCI to an IP address 

E. to map a known IP address to a SPID 

F. to map a known SPID to a MAC address 

Answer:

Explanation: 

http://www.ciscopress.com/articles/article.asp?p=170741&seqNum=4 

Frame-Relay (a Layer 2 protocol) uses Inverse-Arp to map a know Layer 2 Address (DLCI) to a unknow Layer 3 Address. Dynamic Mapping Dynamic address mapping relies on the Frame Relay Inverse Address Resolution Protocol (Inverse ARP), defined by RFC 1293, to resolve a next hop network protocol address to a local DLCI value. The Frame Relay router sends out Inverse ARP requests on its Frame Relay PVC to discover the protocol address of the remote device connected to the Frame Relay network. The responses to the Inverse ARP requests are used to populate an address-to-DLCI mapping table on the Frame Relay router or access server. The router builds and maintains this address-to-DLCI mapping table, which contains all resolved Inverse ARP requests, including both dynamic and static mapping entries. When data needs to be transmitted to a remote destination address, the router performs a lookup on its routing table to determine whether a route to that destination address exists and the next hop address or directly connected interface to use in order to reach that destination. Subsequently, the router consults its address-to-DLCI mapping table for the local DLCI that corresponds to the next hop address. Finally, the router places the frames targeted to the remote destination on its identified outgoing local DLCI. On Cisco routers, dynamic Inverse ARP is enabled by default for all network layer protocols enabled on the physical interface. Packets are not sent out for network layer protocols that are not enabled on the physical interface. For example, no dynamic Inverse ARP resolution is performed for IPX if ipx routing is not enabled globally and there is no active IPX address assigned to the interface. Because dynamic Inverse ARP is enabled by default, no additional Cisco IOS command is required to enable it on an interface. Example 4-16 shows the output of the show frame-relay map privileged EXEC mode command. The addressto-DLCI mapping table displays useful information. The output of the command shows that the next hop address 172.16.1.2 is dynamically mapped to the local DLCI 102, broadcast is enabled on the interface, and the interface's status is currently active. 

NOTE After enabling Frame Relay on the interface, the Cisco router does not perform Inverse ARP until IP routing is enabled on the router. By default, IP routing is enabled on a Cisco router. If IP routing has been turned off, enable IP routing with the ip routing command in the global configuration mode. After IP routing is enabled, the router performs Inverse ARP and begins populating the address-to-DLCI mapping table with resolved entries. 


Q8. - (Topic 1) 

Refer to the exhibit. 

What commands must be configured on the 2950 switch and the router to allow communication between host 1 and host 2? (Choose two.) 

A. Router(config)# interface fastethernet 0/0 Router(config-if)# ip address 192.168.1.1 255.255.255.0 Router(config-if)# no shut down 

B. Router(config)# interface fastethernet 0/0 Router(config-if)# no shut down Router(config)# interface fastethernet 0/0.1 Router(config-subif)# encapsulation dot1q 10 Router(config-subif)# ip address 192.168.10.1 255.255.255.0 

Router(config)# interface fastethernet 0/0.2 Router(config-subif)# encapsulation dot1q 20 Router(config-subif)# ip address 192.168.20.1 255.255.255.0 

C. Router(config)# router eigrp 100 Router(config-router)# network 192.168.10.0 Router(config-router)# network 192.168.20.0 

D. Switch1(config)# vlan database Switch1(config-vlan)# vtp domain XYZ Switch1(config-vlan)# vtp server 

E. Switch1(config)# interface fastethernet 0/1 Switch1(config-if)# switchport mode trunk 

F. Switch1(config)# interface vlan 1 Switch1(config-if)# ip default-gateway 192.168.1.1 

Answer: B,E 

Explanation: 

The two answers B and E list all the commands needed to configure interVLAN routing. Please notice that Cisco switch 2950, 2960 only support dot1Q trunking so we don’t need to specify which trunking encapsulation to use in this case. For Cisco switches 3550 or above we have to use these commands instead: 

Switch3550(config-if)#switchport trunk encapsulation dot1q Switch3550(config-if)#switchport mode trunk 

References: http://www.cisco.com/en/US/tech/tk389/tk815/technologies_configuration_example09186a 00800949fd.shtml https://learningnetwork.cisco.com/servlet/JiveServlet/download/5669-2461/Router%20on%20a%20Stick.pdf. 


Q9. - (Topic 2) 

Refer to the exhibit. 

Given the output from the “show ip eigrp topology” command, which router is the feasible successor? 

A) 

B) 

C) 

D) 

A. Exhibit A 

B. Exhibit B 

C. Exhibit C 

D. Exhibit D 

Answer:

Explanation: 

To be the feasible successor, the Advertised Distance (AD) of that route must be less than the Feasible Distance (FD) of the successor. From the output of the “show ip eigrp topology 

10.0.0.5 255.255.255.255 we learn that the FD of the successor is 41152000. Now we will mention about the answers, in the “Composite metric is (…/…)” statement the first parameter is the FD while the second parameter is the AD of that route. So we need to find out which route has the second parameter (AD) less than 41152000 -> only answer B satisfies this requirement with an AD of 128256. 

Reference: http://networklessons.com/eigrp/eigrp-neighbor-and-topology-table-explained/ 


Q10. - (Topic 3) 

A network administrator needs to configure a serial link between the main office and a remote location. The router at the remote office is a non-Cisco router. How should the network administrator configure the serial interface of the main office router to make the connection? 

A. Main(config)# interface serial 0/0 Main(config-if)# ip address 172.16.1.1 255.255.255.252 Main(config-if)# no shut 

B. Main(config)# interface serial 0/0 Main(config-if)# ip address 172.16.1.1 255.255.255.252 Main(config-if)# encapsulation ppp Main(config-if)# no shut 

C. Main(config)# interface serial 0/0 Main(config-if)# ip address 172.16.1.1 255.255.255.252 Main(config-if)# encapsulation frame-relay Main(config-if)# authentication chap Main(config-if)# no shut 

D. Main(config)# interface serial 0/0 Main(config-if)#ip address 172.16.1.1 255.255.255.252 Main(config-if)#encapsulation ietf Main(config-if)# no shut 

Answer:

Explanation: 

Cisco High-Level Data Link Controller (HDLC) is the Cisco proprietary protocol for sending data over synchronous serial links using HDLC. So HDLC runs only in Cisco router. PPP is not proprietary protocol it's a open source every cisco router and non-cisco router understand the PPP protocol.So we need to configure the PPP protocol if connection is between cisco and non-cisco router.