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Q11. - (Topic 2)
Which address type does a switch use to make selective forwarding decisions?
A. Source IP address
B. Destination IP address
C. Source and destination IP address
D. Source MAC address
E. Destination MAC address
Answer: E
Explanation:
Switches analyze the destination MAC to make its forwarding decision since it is a layer 2 device. Routers use the destination IP address to make forwarding decisions.
Q12. - (Topic 3)
What command sequence will configure a router to run OSPF and add network 10.1.1.0 /24 to area 0?
A. router ospf area 0 network 10.1.1.0 255.255.255.0 area 0
B. router ospf network 10.1.1.0 0.0.0.255
C. router ospf 1 network 10.1.1.0 0.0.0.255 area 0
D. router ospf area 0 network 10.1.1.0 0.0.0.255 area 0
E. router ospf network 10.1.1.0 255.255.255.0 area 0 F. router ospf 1 network 10.1.1.0 0.0.0.255
Answer: C
Explanation:
Enabling OSPFSUMMARY STEPS
1.
enable
2.
configure terminal
3.
router ospf process-id
4.
network ip-address wildcard-mask area area-id
5.
end
DETAILED STEPS
Command or Action Purpose Step.1 enable
Example:
Device> enable Enables privileged EXEC mode. . Enter your password if prompted.
Step.2 configure terminal
Example:
Device# configure terminal Enters global configuration mode.
Step.3 router ospf process-id
Example:
Device(config)# router ospf 109
Enables OSPF routing and enters router configuration mode.
Step.4 network ip-address wildcard-mask area area-id
Example:
Device(config-router)# network 192.168.129.16 0.0.0.3 area 0
Defines an interface on which OSPF runs and defines the area ID for that interface.
Step.5 end
Example:
Device(config-router)# end
Exits router configuration mode and returns to privileged EXEC mode.
Reference: http://www.cisco.com/c/en/us/td/docs/ios-xml/ios/iproute_ospf/configuration/12-4t/iro-12-4t-book/iro-cfg.html#GUID-588D1301-F63C-4DAC-BF1C-C3735EB13673
Q13. - (Topic 7)
Which statement about routing protocols is true?
A. Link-state routing protocols choose a path by the number of hops to the destination.
B. OSPF is a link-state routing protocol.
C. Distance-vector routing protocols use the Shortest Path First algorithm.
D. IS-IS is a distance-vector routing protocol.
Answer: A
Explanation: Link State Routing Protocols
Link state protocols are also called shortest-path-first protocols. Link state routing protocols have a complete picture of the network topology. Hence they know more about the whole network than any distance vector protocol. Three separate tables are created on each link state routing enabled router. One table is used to hold details about directly connected neighbors, one is used to hold the topology of the entire internetwork and the last one is used to hold the actual routing table. Link state protocols send information about directly connected links to all the routers in the network. Examples of Link state routing protocols include OSPF - Open Shortest Path First and IS-IS - Intermediate System to Intermediate System. There are also routing protocols that are considered to be hybrid in the sense that they use aspects of both distance vector and link state protocols. EIGRP - Enhanced Interior Gateway Routing Protocol is one of those hybrid routing protocols.
Q14. - (Topic 3)
Refer to the exhibit.
Which two statements are true about the loopback address that is configured on RouterB? (Choose two.)
A. It ensures that data will be forwarded by RouterB.
B. It provides stability for the OSPF process on RouterB.
C. It specifies that the router ID for RouterB should be 10.0.0.1.
D. It decreases the metric for routes that are advertised from RouterB.
E. It indicates that RouterB should be elected the DR for the LAN.
Answer: B,C
Explanation:
A loopback interface never comes down even if the link is broken so it provides stability for the OSPF process (for example we use that loopback interface as the router-id) -The router-ID is chosen in the order below:
+
The highest IP address assigned to a loopback (logical) interface.
+
If a loopback interface is not defined, the highest IP address of all active router’s physical interfaces will be chosen. -> The loopback interface will be chosen as the router ID of RouterB -
Q15. - (Topic 3)
An administrator is working with the 192.168.4.0 network, which has been subnetted with a /26 mask. Which two addresses can be assigned to hosts within the same subnet? (Choose two.)
A. 192.168.4.61
B. 192.168.4.63
C. 192.168.4.67
D. 192.168.4.125
E. 192.168.4.128
F. 192.168.4.132
Answer: C,D
Explanation:
Increment: 64 (/26 = 11111111.11111111.11111111.11000000)
The IP 192.168.4.0 belongs to class C. The default subnet mask of class C is /24 and it has
been subnetted with a /26 mask so we have 2(26-24).= 22.= 4 sub-networks:
1st subnet: 192.168.4.0 (to 192.168.4.63)
2nd subnet: 192.168.4.64 (to 192.168.4.127)
3rd subnet: 192.168.4.128 (to 192.168.4.191)
4th subnet: 192.168.4.192 (to 192.168.4.225)
In all the answers above, only answer C and D are in the same subnet.
Therefore only IPs in this range can be assigned to hosts.
Q16. - (Topic 4)
When configuring NAT, the Internet interface is considered to be what?
A. local
B. inside
C. global
D. outside
Answer: D
Explanation:
The first step to deploy NAT is to define NAT inside and outside interfaces. You may find it easiest to define your internal network as inside, and the external network as outside. However, the terms internal and external are subject to arbitration as well. This figure shows an example of this.
2a.gif
Reference: http://www.cisco.com/c/en/us/support/docs/ip/network-address-translation-nat/13772-12.html#topic2
Q17. - (Topic 3)
Refer to the exhibit.
Which command would you use to configure a static route on Router1 to network 192.168.202.0/24 with a nondefault administrative distance?
A. router1(config)#ip route 1 192.168.201.1 255.255.255.0 192.168.201.2
B. router1(config)#ip route 192.168.202.0 255.255.255.0 192.168.201.2 1
C. router1(config)#ip route 5 192.168.202.0 255.255.255.0 192.168.201.2
D. router1(config)#ip route 192.168.202.0 255.255.255.0 192.168.201.2 5
Answer: D
Explanation:
The default AD for a static route is 1. To change this, configure a different value to be used as the AD at the very end of the “ip route” statement.
Q18. - (Topic 5)
Refer to the exhibit.
A network administrator has configured a Catalyst 2950 switch for remote management by pasting into the console the configuration commands that are shown in the exhibit. However, a Telnet session cannot be successfully established from a remote host. What should be done to fix this problem?
A. Change the first line to interface fastethernet 0/1.
B. Change the first line to interface vlan 0/1.
C. Change the fifth line to ip default-gateway 192.168.17.241.
D. Change the fifth line to ip route 0.0.0.0 0.0.0.0 192.168.17.1.
E. Change the sixth line to line con 0.
Answer: C
Explanation:
The default gateway must reside on the same IP subnet as the device. Here, the subnet mask for the VLAN interface is /228. Only choice C will fix this issue, as then the default gateway is on the same subnet as the 2950.
Q19. - (Topic 3)
Refer to the exhibit.
Given the output for this command, if the router ID has not been manually set, what router ID will OSPF use for this router?
A. 10.1.1.2
B. 10.154.154.1
C. 172.16.5.1
D. 192.168.5.3
Answer: C
Explanation:
The highest IP address of all loopback interfaces will be chosen -> Loopback 0 will be chosen as the router ID.
Q20. - (Topic 3)
To allow or prevent load balancing to network 172.16.3.0/24, which of the following commands could be used in R2? (Choose two.)
A. R2(config-if)#clock rate
B. R2(config-if)#bandwidth
C. R2(config-if)#ip ospf cost
D. R2(config-if)#ip ospf priority
E. R2(config-router)#distance ospf
Answer: B,C
Explanation:
http://www.cisco.com/en/US/tech/tk365/technologies_white_paper09186a0080094e9e.sht ml#t6
The cost (also called metric) of an interface in OSPF is an indication of the overhead required to send packets across a certain interface. The cost of an interface is inversely proportional to the bandwidth of that interface. A higher bandwidth indicates a lower cost. There is more overhead (higher cost) and time delays involved in crossing a 56k serial line than crossing a 10M Ethernet line. The formula used to calculate the cost is: Cost = 10000 0000/bandwidth in bps For example, it will cost 10 EXP8/10 EXP7 = 10 to cross a 10M Ethernet line and will cost 10 EXP8/1544000 =64 to cross a T1 line. By default, the cost of an interface is calculated based on the bandwidth; you can force the cost of an interface with the ip ospf cost <value> interface subconfiguration mode command.